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4x^2-85x=465
We move all terms to the left:
4x^2-85x-(465)=0
a = 4; b = -85; c = -465;
Δ = b2-4ac
Δ = -852-4·4·(-465)
Δ = 14665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-\sqrt{14665}}{2*4}=\frac{85-\sqrt{14665}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+\sqrt{14665}}{2*4}=\frac{85+\sqrt{14665}}{8} $
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